Monday, March 17, 2008

Problem of the Week #21: March 17th to 21st 2008


Grade 6:
Using the pattern in the following table
find the value of the missing number in the
bottom right corner. 4 9 11
6 8 12
13 16 27
19 26 43
23 7 28
31 47 ?




Grade 7:
Continue the following pattern to find the next 5 terms

17, 8, 25, 7, 32, 5, 37, 10, 47, 11, 58, 13, ___, ____, ____, ____, _____ .

Grade 8:
Find the values of a and b if both the median and the mean of the number set is equal to 8.
{ a, b, 10, 7, 11}

Grade 9: Suppose that 7! is written as a product abcd, where a, b, c, and d are positive integers such that each of a, b, c, and d has the same number of positive integral divisors. (As an example, 6 has four positive integral divisors: 1, 2, 3, and 6.) What is the value of a + b + c + d ?
Grade 10: Can you make the following problem a true statement by repositioning one and only one digit in the equation? You cannot add or subtract any mathematical symbols or move the – or the = signs. Equation: 26 – 63 = 1

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